Write a bash script using an if then else statement that will accept a day of the week from the command line?

Gunner Bartoletti asked a question: Write a bash script using an if then else statement that will accept a day of the week from the command line?
Asked By: Gunner Bartoletti
Date created: Fri, Jun 4, 2021 9:55 PM

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FAQ

Those who are looking for an answer to the question «Write a bash script using an if then else statement that will accept a day of the week from the command line?» often ask the following questions:

💻 Can a bash script take an argument from the command line?

  • One thing you can do is take an argument from the command line. So, for instance, when you run “script foo” the script will take the name of the first argument (foo): Here bash will read the command line and echo (print) the first argument — that is, the first string after the command itself.

💻 How do i run a bash script from the command line?

BASH will be available in the Command Prompt and PowerShell. Open Command Prompt and navigate to the folder where the script file is available. Type Bash script-filename.sh and hit the enter key. It will execute the script, and depending on the file, you should see an output.

💻 Can a bash script read a command line argument?

  • Bash script can read input from command line argument like other programming language. For example, $1 and $2 variable are used to read first and second command line arguments. Create a file named “ command_line.sh ” and add the following script.

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#!/bin/bash if [ "$1" = Wednesday ]; then echo "Homework is Due." else echo "Do your homework." fi This worked for me, however, it's not perfect. This script will also take any input you wish to put it and still echo "Do your homework." For example, I named this script lab5if. To run it on the command line I would type ./lab5if Wednesday. The output will echo "Homework is due." If I enter the rest of the days of the week, as well as, any other entry (bacon etc...) the else statement kicks in.

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