Which is the best operator to compare numbers in bash?

Laisha Spinka asked a question: Which is the best operator to compare numbers in bash?
Asked By: Laisha Spinka
Date created: Sun, May 2, 2021 6:59 PM

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Top best answers to the question «Which is the best operator to compare numbers in bash»

  • Operators for bash compare numbers Detail examples of bash compare numbers operators: 1. -eq operator 2. -ge operator 3. -gt operator You may like:

FAQ

Those who are looking for an answer to the question «Which is the best operator to compare numbers in bash?» often ask the following questions:

💻 How do i compare numbers in bash?

  1. num1 -eq num2 check if 1st number is equal to 2nd number.
  2. num1 -ge num2 checks if 1st number is greater than or equal to 2nd number.
  3. num1 -gt num2 checks if 1st number is greater than 2nd number.
  4. num1 -le num2 checks if 1st number is less than or equal to 2nd number.

💻 How do i compare three numbers in bash?

  1. Get three numbers. Say num1, num2, num2.
  2. If (num1 > num2) and (num1 > num3) echo value of num1.
  3. elif(num2 > num1) and (num2 > num3) echo value of num2.
  4. Otherwise,

💻 How do i compare two numbers in bash?

echo "enter two numbers"; read a b; echo "a=$a"; echo "b=$b"; if [ $a \> $b ]; then echo "a is greater than b"; else echo "b is greater than a"; fi; The problem is that it compares the number from the first digit on, i.e., 9 is bigger than 10, but 1 is greater than 09.

Your Answer

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Comparison Operators

When comparing strings in Bash you can use the following operators: string1 = string2 and string1 == string2 - The equality operator returns true if the operands are equal. Use the = operator with the test [ command. Use the == operator with the [[ command for pattern matching.

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How do i add numbers in bash?

  1. Using expr command with quotes sum=`expr $num1 + $num2`
  2. Use expr command inclosed with brackets and start with dollar symbol. sum=$(expr $num1 + $num2)
  3. This is my preferred way to directly with the shell. sum=$(($num1 + $num2))

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How do i add two numbers in bash?

  1. Using expr command with quotes sum=`expr $num1 + $num2`
  2. Use expr command inclosed with brackets and start with dollar symbol. sum=$(expr $num1 + $num2)
  3. This is my preferred way to directly with the shell. sum=$(($num1 + $num2))

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How to add numbers on a bash script?

bash script example

  1. #!/bin/bash.
  2. echo -n "Enter the first number : "
  3. read num1.
  4. echo -n "Enter the second number : "
  5. read num2.
  6. sum=`expr $num1 + $num2`
  7. echo "sum of two value is $sum"

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How to add two numbers in bash shell script?

bash script example

Bash – Adding Two Numbers

  1. Using expr command with quotes sum=`expr $num1 + $num2`
  2. Use expr command inclosed with brackets and start with dollar symbol. sum=$(expr $num1 + $num2)
  3. This is my preferred way to directly with the shell. sum=$(($num1 + $num2))

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